{
  "course_id": "amu-11th-science-diploma",
  "course_name": "AMU Class 11th Science & Diploma in Engineering Entrance Exam",
  "short_code": "amu-11th-sci",
  "canonical_url": "/amu/11th-science-diploma/pyq/",
  "institution": "Aligarh Muslim University (AMU)",
  "total_years_cataloged": 10,
  "year_range": "2015-2024",
  "exam_structure": {
    "duration_minutes": 120,
    "total_marks": 100,
    "total_questions": 100,
    "marking_scheme": {
      "correct": 1.0,
      "incorrect": -0.25,
      "unattempted": 0.0
    },
    "sections": {
      "Science": 50,
      "Mathematics": 30,
      "Indo-Islamic Culture": 10,
      "General Knowledge": 5,
      "English": 5
    }
  },
  "papers": [
    {
      "year": 2024,
      "paper_id": "amu-11th-sci-2024",
      "title": "AMU Class 11 Science & Diploma Entrance 2024 Question Paper with Solutions",
      "exam_date": "2024-05-19",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2024.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2024-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2024-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2024 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2024 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2024-q1",
          "question_number": 1,
          "subject": "Physics",
          "topic": "Electricity",
          "difficulty": "Medium",
          "question": "A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R', then the ratio R/R' is:",
          "options": {
            "A": "1/25",
            "B": "1/5",
            "C": "5",
            "D": "25"
          },
          "correct_answer": "D",
          "explanation": "When a wire of resistance R is cut into 5 equal parts, the resistance of each part becomes r = R/5. When these 5 resistors of resistance R/5 are connected in parallel, the equivalent resistance 1/R' = 1/r + 1/r + 1/r + 1/r + 1/r = 5/r = 5/(R/5) = 25/R. Therefore, R' = R/25, which gives the ratio R/R' = 25.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Resistance of wire cut into 5 equal parts and connected in parallel",
            "text": "A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R', then the ratio R/R' is:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "1/25"
              },
              {
                "@type": "Answer",
                "text": "1/5"
              },
              {
                "@type": "Answer",
                "text": "5"
              },
              {
                "@type": "Answer",
                "text": "25"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "25. Each piece has resistance R/5; five pieces in parallel yield R' = R/25, hence R/R' = 25."
            }
          }
        },
        {
          "id": "amu-11th-2024-q2",
          "question_number": 18,
          "subject": "Chemistry",
          "topic": "Acids, Bases & Salts",
          "difficulty": "Easy",
          "question": "Which of the following salts does NOT contain water of crystallization?",
          "options": {
            "A": "Blue Vitriol",
            "B": "Baking Soda",
            "C": "Washing Soda",
            "D": "Gypsum"
          },
          "correct_answer": "B",
          "explanation": "Baking soda is Sodium Hydrogen Carbonate (NaHCO3) and contains no water of crystallization. In contrast, Blue Vitriol is CuSO4·5H2O (5 water molecules), Washing Soda is Na2CO3·10H2O (10 water molecules), and Gypsum is CaSO4·2H2O (2 water molecules).",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Which salt does not contain water of crystallization?",
            "text": "Which of the following salts does NOT contain water of crystallization?",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "Blue Vitriol"
              },
              {
                "@type": "Answer",
                "text": "Baking Soda"
              },
              {
                "@type": "Answer",
                "text": "Washing Soda"
              },
              {
                "@type": "Answer",
                "text": "Gypsum"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "Baking Soda (NaHCO3) does not contain water of crystallization."
            }
          }
        },
        {
          "id": "amu-11th-2024-q3",
          "question_number": 35,
          "subject": "Biology",
          "topic": "Life Processes",
          "difficulty": "Easy",
          "question": "The breakdown of pyruvate to give carbon dioxide, water and energy takes place in:",
          "options": {
            "A": "Cytoplasm",
            "B": "Mitochondria",
            "C": "Chloroplast",
            "D": "Nucleus"
          },
          "correct_answer": "B",
          "explanation": "Glycolysis (conversion of glucose to pyruvate) occurs in the cytoplasm without oxygen. Aerobic breakdown of pyruvate into carbon dioxide, water, and 36-38 ATP units occurs inside the mitochondria (Krebs cycle).",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Where does aerobic breakdown of pyruvate occur?",
            "text": "The breakdown of pyruvate to give carbon dioxide, water and energy takes place in:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "Cytoplasm"
              },
              {
                "@type": "Answer",
                "text": "Mitochondria"
              },
              {
                "@type": "Answer",
                "text": "Chloroplast"
              },
              {
                "@type": "Answer",
                "text": "Nucleus"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "Mitochondria."
            }
          }
        },
        {
          "id": "amu-11th-2024-q4",
          "question_number": 55,
          "subject": "Mathematics",
          "topic": "Arithmetic Progressions",
          "difficulty": "Medium",
          "question": "If the sum of first n terms of an AP is given by Sn = 3n^2 + 5n, then its 15th term is:",
          "options": {
            "A": "86",
            "B": "92",
            "C": "98",
            "D": "104"
          },
          "correct_answer": "B",
          "explanation": "The n-th term an = Sn - S(n-1). Alternatively, a1 = S1 = 3(1)^2 + 5(1) = 8. S2 = 3(2)^2 + 5(2) = 12 + 10 = 22. So second term a2 = S2 - S1 = 22 - 8 = 14. Common difference d = a2 - a1 = 14 - 8 = 6. The 15th term a15 = a1 + 14d = 8 + 14(6) = 8 + 84 = 92.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Find the 15th term of AP given Sn = 3n^2 + 5n",
            "text": "If the sum of first n terms of an AP is given by Sn = 3n^2 + 5n, then its 15th term is:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "86"
              },
              {
                "@type": "Answer",
                "text": "92"
              },
              {
                "@type": "Answer",
                "text": "98"
              },
              {
                "@type": "Answer",
                "text": "104"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "92. Using an = Sn - S(n-1) gives a15 = S15 - S14 = 750 - 658 = 92."
            }
          }
        },
        {
          "id": "amu-11th-2024-q5",
          "question_number": 82,
          "subject": "Indo-Islamic Culture",
          "topic": "Aligarh Movement",
          "difficulty": "Easy",
          "question": "Who laid the foundation stone of MAO College on January 8, 1877?",
          "options": {
            "A": "Lord Ripon",
            "B": "Lord Curzon",
            "C": "Lord Lytton",
            "D": "Lord Mayo"
          },
          "correct_answer": "C",
          "explanation": "Viceroy Lord Lytton laid the foundation stone of Muhammadan Anglo-Oriental (MAO) College at Aligarh on January 8, 1877.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Who laid the foundation stone of MAO College?",
            "text": "Who laid the foundation stone of MAO College on January 8, 1877?",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "Lord Ripon"
              },
              {
                "@type": "Answer",
                "text": "Lord Curzon"
              },
              {
                "@type": "Answer",
                "text": "Lord Lytton"
              },
              {
                "@type": "Answer",
                "text": "Lord Mayo"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "Lord Lytton."
            }
          }
        }
      ]
    },
    {
      "year": 2023,
      "paper_id": "amu-11th-sci-2023",
      "title": "AMU Class 11 Science & Diploma Entrance 2023 Solved Paper",
      "exam_date": "2023-05-21",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2023.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2023-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2023-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2023 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2023 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2023-q1",
          "question_number": 1,
          "subject": "Physics",
          "topic": "Light: Reflection & Refraction",
          "difficulty": "Medium",
          "question": "An object 4.0 cm in size is placed at 25.0 cm in front of a concave mirror of focal length 15.0 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image?",
          "options": {
            "A": "-37.5 cm",
            "B": "-30.0 cm",
            "C": "-45.0 cm",
            "D": "-20.0 cm"
          },
          "correct_answer": "A",
          "explanation": "Using mirror formula 1/v + 1/u = 1/f with sign conventions: u = -25 cm, f = -15 cm. 1/v = 1/f - 1/u = -1/15 - (-1/25) = -1/15 + 1/25 = (-5 + 3)/75 = -2/75. Hence v = -75/2 = -37.5 cm in front of the mirror.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Light: Reflection & Refraction",
            "text": "An object 4.0 cm in size is placed at 25.0 cm in front of a concave mirror of focal length 15.0 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image?",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "-37.5 cm"
              },
              {
                "@type": "Answer",
                "text": "-30.0 cm"
              },
              {
                "@type": "Answer",
                "text": "-45.0 cm"
              },
              {
                "@type": "Answer",
                "text": "-20.0 cm"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "-37.5 cm"
            }
          }
        }
      ]
    },
    {
      "year": 2022,
      "paper_id": "amu-11th-sci-2022",
      "title": "AMU Class 11 Science & Diploma Entrance 2022 Solved Paper",
      "exam_date": "2022-07-24",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2022.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2022-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2022-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2022 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2022 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2022-q1",
          "question_number": 1,
          "subject": "Mathematics",
          "topic": "Trigonometry",
          "difficulty": "Medium",
          "question": "If sin theta + cos theta = sqrt(2) cos theta, then the value of cos theta - sin theta is:",
          "options": {
            "A": "sqrt(2) sin theta",
            "B": "sqrt(2) cos theta",
            "C": "1/sqrt(2) sin theta",
            "D": "2 sin theta"
          },
          "correct_answer": "A",
          "explanation": "Given sin theta = (sqrt(2) - 1) cos theta. Multiply both sides by (sqrt(2) + 1): (sqrt(2) + 1) sin theta = (2 - 1) cos theta = cos theta. Therefore, sqrt(2) sin theta + sin theta = cos theta, which rearranges to cos theta - sin theta = sqrt(2) sin theta.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Trigonometry",
            "text": "If sin theta + cos theta = sqrt(2) cos theta, then the value of cos theta - sin theta is:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "sqrt(2) sin theta"
              },
              {
                "@type": "Answer",
                "text": "sqrt(2) cos theta"
              },
              {
                "@type": "Answer",
                "text": "1/sqrt(2) sin theta"
              },
              {
                "@type": "Answer",
                "text": "2 sin theta"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "sqrt(2) sin theta"
            }
          }
        }
      ]
    },
    {
      "year": 2021,
      "paper_id": "amu-11th-sci-2021",
      "title": "AMU Class 11 Science & Diploma Entrance 2021 Solved Paper",
      "exam_date": "2021-09-26",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2021.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2021-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2021-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2021 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2021 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2021-q1",
          "question_number": 1,
          "subject": "Chemistry",
          "topic": "Chemical Reactions & Equations",
          "difficulty": "Easy",
          "question": "Which of the following gases is flushed into bags of potato chips to prevent rancidity?",
          "options": {
            "A": "Oxygen",
            "B": "Nitrogen",
            "C": "Hydrogen",
            "D": "Carbon Monoxide"
          },
          "correct_answer": "B",
          "explanation": "Nitrogen gas is an unreactive antioxidant gas flushed into food packets and chip bags to displace oxygen and prevent oxidative degradation (rancidity) of oils and fats.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Chemical Reactions & Equations",
            "text": "Which of the following gases is flushed into bags of potato chips to prevent rancidity?",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "Oxygen"
              },
              {
                "@type": "Answer",
                "text": "Nitrogen"
              },
              {
                "@type": "Answer",
                "text": "Hydrogen"
              },
              {
                "@type": "Answer",
                "text": "Carbon Monoxide"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "Nitrogen"
            }
          }
        }
      ]
    },
    {
      "year": 2020,
      "paper_id": "amu-11th-sci-2020",
      "title": "AMU Class 11 Science & Diploma Entrance 2020 Solved Paper",
      "exam_date": "2020-11-22",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2020.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2020-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2020-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2020 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2020 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2020-q1",
          "question_number": 1,
          "subject": "Mathematics",
          "topic": "Quadratic Equations",
          "difficulty": "Medium",
          "question": "If one root of the quadratic equation 2x^2 + kx - 6 = 0 is 2, then the value of k is:",
          "options": {
            "A": "-1",
            "B": "1",
            "C": "-2",
            "D": "2"
          },
          "correct_answer": "A",
          "explanation": "Since x = 2 is a root, substitute x = 2 into 2(2)^2 + k(2) - 6 = 0: 2(4) + 2k - 6 = 0 => 8 + 2k - 6 = 0 => 2k + 2 = 0 => k = -1.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Quadratic Equations",
            "text": "If one root of the quadratic equation 2x^2 + kx - 6 = 0 is 2, then the value of k is:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "-1"
              },
              {
                "@type": "Answer",
                "text": "1"
              },
              {
                "@type": "Answer",
                "text": "-2"
              },
              {
                "@type": "Answer",
                "text": "2"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "-1"
            }
          }
        }
      ]
    },
    {
      "year": 2019,
      "paper_id": "amu-11th-sci-2019",
      "title": "AMU Class 11 Science & Diploma Entrance 2019 Solved Paper",
      "exam_date": "2019-04-28",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2019.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2019-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2019-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2019 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2019 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2019-q1",
          "question_number": 1,
          "subject": "Biology",
          "topic": "Heredity & Evolution",
          "difficulty": "Easy",
          "question": "In pea plants, a pure tall plant (TT) is crossed with a short plant (tt). The ratio of pure tall plants to short plants in F2 generation will be:",
          "options": {
            "A": "1:1",
            "B": "3:1",
            "C": "1:3",
            "D": "2:1"
          },
          "correct_answer": "A",
          "explanation": "In the F2 generation of a monohybrid cross, genotypic ratio is 1 TT (pure tall) : 2 Tt (hybrid tall) : 1 tt (pure short). Thus the ratio of pure tall (TT) to short plants (tt) is 1:1.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Heredity & Evolution",
            "text": "In pea plants, a pure tall plant (TT) is crossed with a short plant (tt). The ratio of pure tall plants to short plants in F2 generation will be:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "1:1"
              },
              {
                "@type": "Answer",
                "text": "3:1"
              },
              {
                "@type": "Answer",
                "text": "1:3"
              },
              {
                "@type": "Answer",
                "text": "2:1"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "1:1"
            }
          }
        }
      ]
    },
    {
      "year": 2018,
      "paper_id": "amu-11th-sci-2018",
      "title": "AMU Class 11 Science & Diploma Entrance 2018 Solved Paper",
      "exam_date": "2018-04-29",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2018.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2018-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2018-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2018 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2018 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2018-q1",
          "question_number": 1,
          "subject": "Indo-Islamic Culture",
          "topic": "Sir Syed Chronology",
          "difficulty": "Easy",
          "question": "In which year did Sir Syed Ahmad Khan establish the Scientific Society at Ghazipur?",
          "options": {
            "A": "1860",
            "B": "1864",
            "C": "1870",
            "D": "1875"
          },
          "correct_answer": "B",
          "explanation": "Sir Syed founded the Scientific Society on January 9, 1864, at Ghazipur to translate scientific texts from English into Urdu.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Sir Syed Chronology",
            "text": "In which year did Sir Syed Ahmad Khan establish the Scientific Society at Ghazipur?",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "1860"
              },
              {
                "@type": "Answer",
                "text": "1864"
              },
              {
                "@type": "Answer",
                "text": "1870"
              },
              {
                "@type": "Answer",
                "text": "1875"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "1864"
            }
          }
        }
      ]
    },
    {
      "year": 2017,
      "paper_id": "amu-11th-sci-2017",
      "title": "AMU Class 11 Science & Diploma Entrance 2017 Solved Paper",
      "exam_date": "2017-05-07",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2017.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2017-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2017-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2017 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2017 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2017-q1",
          "question_number": 1,
          "subject": "Physics",
          "topic": "Work and Energy",
          "difficulty": "Medium",
          "question": "If the velocity of a moving body is doubled, its kinetic energy becomes:",
          "options": {
            "A": "Doubled",
            "B": "Halved",
            "C": "Four times",
            "D": "Eight times"
          },
          "correct_answer": "C",
          "explanation": "Kinetic Energy KE = (1/2)mv^2. If velocity v is doubled to 2v, new KE' = (1/2)m(2v)^2 = 4 * ((1/2)mv^2) = 4 * KE. It quadruples.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Work and Energy",
            "text": "If the velocity of a moving body is doubled, its kinetic energy becomes:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "Doubled"
              },
              {
                "@type": "Answer",
                "text": "Halved"
              },
              {
                "@type": "Answer",
                "text": "Four times"
              },
              {
                "@type": "Answer",
                "text": "Eight times"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "Four times"
            }
          }
        }
      ]
    },
    {
      "year": 2016,
      "paper_id": "amu-11th-sci-2016",
      "title": "AMU Class 11 Science & Diploma Entrance 2016 Solved Paper",
      "exam_date": "2016-05-15",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2016.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2016-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2016-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2016 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2016 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2016-q1",
          "question_number": 1,
          "subject": "Chemistry",
          "topic": "Metals and Non-metals",
          "difficulty": "Easy",
          "question": "Which of the following metals is stored under kerosene oil to prevent accidental fire?",
          "options": {
            "A": "Sodium",
            "B": "Iron",
            "C": "Magnesium",
            "D": "Copper"
          },
          "correct_answer": "A",
          "explanation": "Alkali metals like Sodium (Na) and Potassium (K) are highly reactive and react vigorously with atmospheric moisture and oxygen, catching fire. They are immersed in kerosene oil.",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Metals and Non-metals",
            "text": "Which of the following metals is stored under kerosene oil to prevent accidental fire?",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "Sodium"
              },
              {
                "@type": "Answer",
                "text": "Iron"
              },
              {
                "@type": "Answer",
                "text": "Magnesium"
              },
              {
                "@type": "Answer",
                "text": "Copper"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "Sodium"
            }
          }
        }
      ]
    },
    {
      "year": 2015,
      "paper_id": "amu-11th-sci-2015",
      "title": "AMU Class 11 Science & Diploma Entrance 2015 Solved Paper",
      "exam_date": "2015-05-17",
      "total_questions": 100,
      "duration_minutes": 120,
      "download_urls": {
        "question_paper_pdf": "/assets/pdfs/pyqs/amu-11th-science-2015.pdf",
        "answer_key_pdf": "/assets/pdfs/pyqs/amu-11th-science-2015-answer-key.pdf",
        "solved_solutions_pdf": "/assets/pdfs/pyqs/amu-11th-science-2015-solutions.pdf"
      },
      "subject_breakdown": {
        "Science": 50,
        "Mathematics": 30,
        "Indo-Islamic Culture": 10,
        "General Knowledge": 5,
        "English": 5
      },
      "schema": {
        "@context": "https://schema.org",
        "@type": "LearningResource",
        "name": "AMU Class 11 Science Entrance 2015 Question Paper with Solutions",
        "description": "Download free PDF and access solved questions with detailed step-by-step explanations for the AMU Class 11 Science and Diploma in Engineering 2015 entrance exam.",
        "learningResourceType": "Exam / Previous Year Question Paper",
        "educationalLevel": "Secondary / Higher Secondary School",
        "inLanguage": "en",
        "isAccessibleForFree": true
      },
      "sample_solved_questions": [
        {
          "id": "amu-11th-2015-q1",
          "question_number": 1,
          "subject": "Mathematics",
          "topic": "Coordinate Geometry",
          "difficulty": "Easy",
          "question": "The distance between the points P(2, 3) and Q(4, 1) is:",
          "options": {
            "A": "2",
            "B": "2 sqrt(2)",
            "C": "4",
            "D": "sqrt(10)"
          },
          "correct_answer": "B",
          "explanation": "Distance d = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((4 - 2)^2 + (1 - 3)^2) = sqrt(2^2 + (-2)^2) = sqrt(4 + 4) = sqrt(8) = 2 sqrt(2).",
          "schema": {
            "@context": "https://schema.org",
            "@type": "Question",
            "name": "Coordinate Geometry",
            "text": "The distance between the points P(2, 3) and Q(4, 1) is:",
            "suggestedAnswer": [
              {
                "@type": "Answer",
                "text": "2"
              },
              {
                "@type": "Answer",
                "text": "2 sqrt(2)"
              },
              {
                "@type": "Answer",
                "text": "4"
              },
              {
                "@type": "Answer",
                "text": "sqrt(10)"
              }
            ],
            "acceptedAnswer": {
              "@type": "Answer",
              "text": "2 sqrt(2)"
            }
          }
        }
      ]
    }
  ]
}